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12022103 is a prime number
BaseRepresentation
bin101101110111…
…000101010111
3211121210020002
4231313011113
511034201403
61105401515
7204120602
oct55670527
924553202
1012022103
116871425
12403929b
13264c092
14184d339
1510c7188
hexb77157

12022103 has 2 divisors, whose sum is σ = 12022104. Its totient is φ = 12022102.

The previous prime is 12022097. The next prime is 12022133. The reversal of 12022103 is 30122021.

It is a happy number.

12022103 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30122021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12022103 - 26 = 12022039 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12022133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011051 + 6011052.

It is an arithmetic number, because the mean of its divisors is an integer number (6011052).

Almost surely, 212022103 is an apocalyptic number.

12022103 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022103 is an equidigital number, since it uses as much as digits as its factorization.

12022103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 11.

The square root of 12022103 is about 3467.2904406755. The cubic root of 12022103 is about 229.0833268456.

Adding to 12022103 its reverse (30122021), we get a palindrome (42144124).

The spelling of 12022103 in words is "twelve million, twenty-two thousand, one hundred three".