Base | Representation |
---|---|
bin | 10110011001001001… |
… | …10000001010011000 |
3 | 1011000211202000210220 |
4 | 23030210300022120 |
5 | 144110130333422 |
6 | 5304535440040 |
7 | 603630225531 |
oct | 131444601230 |
9 | 34024660726 |
10 | 12022121112 |
11 | 510a1a0591 |
12 | 23b6226020 |
13 | 119790b541 |
14 | 820939688 |
15 | 4a568ee5c |
hex | 2cc930298 |
12022121112 has 32 divisors (see below), whose sum is σ = 30085508400. Its totient is φ = 4003346304.
The previous prime is 12022121107. The next prime is 12022121197. The reversal of 12022121112 is 21112122021.
It is a super-2 number, since 2×120221211122 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12022121091 and 12022121100.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 227287 + ... + 275142.
Almost surely, 212022121112 is an apocalyptic number.
12022121112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12022121112 is an abundant number, since it is smaller than the sum of its proper divisors (18063387288).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12022121112 is a wasteful number, since it uses less digits than its factorization.
12022121112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 503435 (or 503431 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 12022121112 its reverse (21112122021), we get a palindrome (33134243133).
Subtracting 12022121112 from its reverse (21112122021), we obtain a palindrome (9090000909).
The spelling of 12022121112 in words is "twelve billion, twenty-two million, one hundred twenty-one thousand, one hundred twelve".
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