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1202221201103 = 1392478553931
BaseRepresentation
bin10001011111101001111…
…101111011011011001111
311020221010212021211001222
4101133221331323123033
5124144122111413403
62320143124353555
7152600106413006
oct21375175733317
94227125254058
101202221201103
1142394a58738a
12174bb95458bb
13894a48303a0
144228b523c3d
1521414be4338
hex117e9f7b6cf

1202221201103 has 4 divisors (see below), whose sum is σ = 1294699755048. Its totient is φ = 1109742647160.

The previous prime is 1202221201099. The next prime is 1202221201147. The reversal of 1202221201103 is 3011021222021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1202221201103 - 22 = 1202221201099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1202221209103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46239276953 + ... + 46239276978.

It is an arithmetic number, because the mean of its divisors is an integer number (323674938762).

Almost surely, 21202221201103 is an apocalyptic number.

1202221201103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1202221201103 is a deficient number, since it is larger than the sum of its proper divisors (92478553945).

1202221201103 is an equidigital number, since it uses as much as digits as its factorization.

1202221201103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 92478553944.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1202221201103 its reverse (3011021222021), we get a palindrome (4213242423124).

The spelling of 1202221201103 in words is "one trillion, two hundred two billion, two hundred twenty-one million, two hundred one thousand, one hundred three".

Divisors: 1 13 92478553931 1202221201103