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120422120000 = 265471333083
BaseRepresentation
bin111000000100110110…
…1111011101001000000
3102111211102110112021112
41300021231323221000
53433111030320000
6131153211542452
711462113062650
oct1601155735100
9374742415245
10120422120000
1147086169126
121b40915aa28
13b4817a2010
145b85428360
1531ec088235
hex1c09b7ba40

120422120000 has 280 divisors, whose sum is σ = 367528303296. Its totient is φ = 38110464000.

The previous prime is 120422119997. The next prime is 120422120003. The reversal of 120422120000 is 21224021.

It is an interprime number because it is at equal distance from previous prime (120422119997) and next prime (120422120003).

It is a tau number, because it is divible by the number of its divisors (280).

It is a Harshad number since it is a multiple of its sum of digits (14).

It is not an unprimeable number, because it can be changed into a prime (120422120003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 3623459 + ... + 3656541.

Almost surely, 2120422120000 is an apocalyptic number.

120422120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120422120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (183764151648).

120422120000 is an abundant number, since it is smaller than the sum of its proper divisors (247106183296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120422120000 is an equidigital number, since it uses as much as digits as its factorization.

120422120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33135 (or 33110 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 14.

Adding to 120422120000 its reverse (21224021), we get a palindrome (120443344021).

It can be divided in two parts, 1204221 and 20000, that added together give a palindrome (1224221).

The spelling of 120422120000 in words is "one hundred twenty billion, four hundred twenty-two million, one hundred twenty thousand".