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120434405224115 = 5231047255697601
BaseRepresentation
bin11011011000100011010001…
…111100010010111010110011
3120210102102020202211212202002
4123120203101330102322303
5111241144130214132430
61104050445120244215
734240045555521053
oct3330432174227263
9523372222755662
10120434405224115
1135412a43037724
1211610bb277066b
135227bb99a1b98
1421a50b0755563
15ddcb96794845
hex6d88d1f12eb3

120434405224115 has 8 divisors (see below), whose sum is σ = 150804820454688. Its totient is φ = 92158501388800.

The previous prime is 120434405224103. The next prime is 120434405224129. The reversal of 120434405224115 is 511422504434021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 120434405224115 - 218 = 120434404961971 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 523627848686 + ... + 523627848915.

It is an arithmetic number, because the mean of its divisors is an integer number (18850602556836).

Almost surely, 2120434405224115 is an apocalyptic number.

120434405224115 is a deficient number, since it is larger than the sum of its proper divisors (30370415230573).

120434405224115 is a wasteful number, since it uses less digits than its factorization.

120434405224115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1047255697629.

The product of its (nonzero) digits is 153600, while the sum is 38.

Adding to 120434405224115 its reverse (511422504434021), we get a palindrome (631856909658136).

The spelling of 120434405224115 in words is "one hundred twenty trillion, four hundred thirty-four billion, four hundred five million, two hundred twenty-four thousand, one hundred fifteen".

Divisors: 1 5 23 115 1047255697601 5236278488005 24086881044823 120434405224115