12053161450215 has 64 divisors (see below), whose sum is σ = 21461921395200. Its totient is φ = 6418133356032.

The previous prime is 12053161450193. The next prime is 12053161450237. The reversal of 12053161450215 is 51205416135021.

12053161450215 is a `hidden beast` number, since 1 + 2 + 0 + 5 + 31 + 614 + 5 + 0 + 2 + 1 + 5 = 666.

It is an interprime number because it is at equal distance from previous prime (12053161450193) and next prime (12053161450237).

It is not a de Polignac number, because 12053161450215 - 2⁷ = 12053161450087 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12053161450215.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 513478719 + ... + 513502191.

It is an arithmetic number, because the mean of its divisors is an integer number (335342521800).

Almost surely, 2^{12053161450215} is an apocalyptic number.

12053161450215 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12053161450215 is a deficient number, since it is larger than the sum of its proper divisors (9408759944985).

12053161450215 is a wasteful number, since it uses less digits than its factorization.

12053161450215 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29373 (or 29367 counting only the distinct ones).

The product of its (nonzero) digits is 36000, while the sum is 36.

Adding to 12053161450215 its reverse (51205416135021), we get a palindrome (63258577585236).

The spelling of 12053161450215 in words is "twelve trillion, fifty-three billion, one hundred sixty-one million, four hundred fifty thousand, two hundred fifteen".