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121000000333 is a prime number
BaseRepresentation
bin111000010110000101…
…0010111101101001101
3102120022200211220001211
41300230022113231031
53440302000002313
6131330413534421
711512331014162
oct1605412275515
9376280756054
10121000000333
1147352389183
121b54a7a4411
13b544424744
145bdc094069
153232b86e3d
hex1c2c297b4d

121000000333 has 2 divisors, whose sum is σ = 121000000334. Its totient is φ = 121000000332.

The previous prime is 121000000313. The next prime is 121000000367. The reversal of 121000000333 is 333000000121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92672754084 + 28327246249 = 304422^2 + 168307^2 .

It is a cyclic number.

It is not a de Polignac number, because 121000000333 - 229 = 120463129421 is a prime.

It is a super-2 number, since 2×1210000003332 (a number of 23 digits) contains 22 as substring.

121000000333 is a modest number, since divided by 333 gives 121 as remainder.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121000000313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500000166 + 60500000167.

It is an arithmetic number, because the mean of its divisors is an integer number (60500000167).

Almost surely, 2121000000333 is an apocalyptic number.

It is an amenable number.

121000000333 is a deficient number, since it is larger than the sum of its proper divisors (1).

121000000333 is an equidigital number, since it uses as much as digits as its factorization.

121000000333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 121000000333 its reverse (333000000121), we get a palindrome (454000000454).

The spelling of 121000000333 in words is "one hundred twenty-one billion, three hundred thirty-three", and thus it is an aban number.