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333000000121 = 6191031521789
BaseRepresentation
bin1001101100010000101…
…10001100001001111001
31011211112100020201121211
410312020112030021321
520423441000000441
6412551133403121
733026023204255
oct4661026141171
91154470221554
10333000000121
11119251900878
12546550394a1
132552b8a82b9
141218db93265
1589de87ba81
hex4d8858c279

333000000121 has 8 divisors (see below), whose sum is σ = 333862113600. Its totient is φ = 332138933520.

The previous prime is 333000000103. The next prime is 333000000127. The reversal of 333000000121 is 121000000333.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 333000000121 - 225 = 332966445689 is a prime.

It is a super-2 number, since 2×3330000001212 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (333000000127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 377295 + ... + 899083.

It is an arithmetic number, because the mean of its divisors is an integer number (41732764200).

Almost surely, 2333000000121 is an apocalyptic number.

It is an amenable number.

333000000121 is a deficient number, since it is larger than the sum of its proper divisors (862113479).

333000000121 is a wasteful number, since it uses less digits than its factorization.

333000000121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 523439.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 333000000121 its reverse (121000000333), we get a palindrome (454000000454).

The spelling of 333000000121 in words is "three hundred thirty-three billion, one hundred twenty-one", and thus it is an aban number.

Divisors: 1 619 1031 521789 638189 322987391 537964459 333000000121