Base | Representation |
---|---|
bin | 1011000000010100001100… |
… | …1100101110001011111000 |
3 | 1120211202100022022222220010 |
4 | 2300011003030232023320 |
5 | 3041221400332444313 |
6 | 41422404130501520 |
7 | 2356125345246321 |
oct | 260050314561370 |
9 | 46752308288803 |
10 | 12100050281208 |
11 | 3945669a32a1a |
12 | 14350a24348a0 |
13 | 69a050755706 |
14 | 2db9075ab448 |
15 | 15eb3b78d4c3 |
hex | b014332e2f8 |
12100050281208 has 16 divisors (see below), whose sum is σ = 30250125703080. Its totient is φ = 4033350093728.
The previous prime is 12100050281171. The next prime is 12100050281227. The reversal of 12100050281208 is 80218205000121.
It is a super-2 number, since 2×121000502812082 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252084380835 + ... + 252084380882.
Almost surely, 212100050281208 is an apocalyptic number.
It is an amenable number.
12100050281208 is an abundant number, since it is smaller than the sum of its proper divisors (18150075421872).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12100050281208 is a wasteful number, since it uses less digits than its factorization.
12100050281208 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 504168761726 (or 504168761722 counting only the distinct ones).
The product of its (nonzero) digits is 2560, while the sum is 30.
Adding to 12100050281208 its reverse (80218205000121), we get a palindrome (92318255281329).
The spelling of 12100050281208 in words is "twelve trillion, one hundred billion, fifty million, two hundred eighty-one thousand, two hundred eight".
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