Base | Representation |
---|---|
bin | 1011000000010100011000… |
… | …1010110110010110010111 |
3 | 1120211202110210010011121122 |
4 | 2300011012022312112113 |
5 | 3041222001112401012 |
6 | 41422413111034155 |
7 | 2356126522011632 |
oct | 260050612662627 |
9 | 46752423104548 |
10 | 12100100122007 |
11 | 3945695085067 |
12 | 14350b706b95b |
13 | 69a05ab86501 |
14 | 2db910062c19 |
15 | 15eb40d35e72 |
hex | b01462b6597 |
12100100122007 has 2 divisors, whose sum is σ = 12100100122008. Its totient is φ = 12100100122006.
The previous prime is 12100100121971. The next prime is 12100100122009. The reversal of 12100100122007 is 70022100100121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12100100122007 is a prime.
Together with 12100100122009, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12100100122009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050050061003 + 6050050061004.
It is an arithmetic number, because the mean of its divisors is an integer number (6050050061004).
Almost surely, 212100100122007 is an apocalyptic number.
12100100122007 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100100122007 is an equidigital number, since it uses as much as digits as its factorization.
12100100122007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 12100100122007 its reverse (70022100100121), we get a palindrome (82122200222128).
The spelling of 12100100122007 in words is "twelve trillion, one hundred billion, one hundred million, one hundred twenty-two thousand, seven".
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