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121002001200011 is a prime number
BaseRepresentation
bin11011100000110011111001…
…010011000111001110001011
3120212102200022111210221202102
4123200303321103013032023
5111324444044301400021
61105203315120024015
734326051250643441
oct3340637123071613
9525380274727672
10121002001200011
113561172a186308
12116a2bb946200b
13526959419cb19
1421c47571a4b91
15dec81691a00b
hex6e0cf94c738b

121002001200011 has 2 divisors, whose sum is σ = 121002001200012. Its totient is φ = 121002001200010.

The previous prime is 121002001199987. The next prime is 121002001200013. The reversal of 121002001200011 is 110002100200121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121002001200011 - 222 = 121001997005707 is a prime.

Together with 121002001200013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 121002001199965 and 121002001200001.

It is not a weakly prime, because it can be changed into another prime (121002001200013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60501000600005 + 60501000600006.

It is an arithmetic number, because the mean of its divisors is an integer number (60501000600006).

Almost surely, 2121002001200011 is an apocalyptic number.

121002001200011 is a deficient number, since it is larger than the sum of its proper divisors (1).

121002001200011 is an equidigital number, since it uses as much as digits as its factorization.

121002001200011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 121002001200011 its reverse (110002100200121), we get a palindrome (231004101400132).

The spelling of 121002001200011 in words is "one hundred twenty-one trillion, two billion, one million, two hundred thousand, eleven".