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121002101112 = 2335041754213
BaseRepresentation
bin111000010110001001…
…0011000100101111000
3102120022211210121210110
41300230102120211320
53440303014213422
6131330530544320
711512354613664
oct1605422304570
9376284717713
10121002101112
1147353593562
121b54b4380a0
13b5449ab9c9
145bdc47d8a4
153232e4e60c
hex1c2c498978

121002101112 has 16 divisors (see below), whose sum is σ = 302505252840. Its totient is φ = 40334033696.

The previous prime is 121002101111. The next prime is 121002101123. The reversal of 121002101112 is 211101200121.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121002101111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2520877083 + ... + 2520877130.

Almost surely, 2121002101112 is an apocalyptic number.

121002101112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

121002101112 is an abundant number, since it is smaller than the sum of its proper divisors (181503151728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121002101112 is a wasteful number, since it uses less digits than its factorization.

121002101112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5041754222 (or 5041754218 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 12.

Adding to 121002101112 its reverse (211101200121), we get a palindrome (332103301233).

Subtracting 121002101112 from its reverse (211101200121), we obtain a palindrome (90099099009).

The spelling of 121002101112 in words is "one hundred twenty-one billion, two million, one hundred one thousand, one hundred twelve".

Divisors: 1 2 3 4 6 8 12 24 5041754213 10083508426 15125262639 20167016852 30250525278 40334033704 60501050556 121002101112