121002101113 has 4 divisors (see below), whose sum is σ = 121009843108. Its totient is φ = 120994359120.

The previous prime is 121002101111. The next prime is 121002101123. The reversal of 121002101113 is 311101200121.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311101200121 = 11071 ⋅28100551.

It can be written as a sum of positive squares in 2 ways, for example, as 58546093369 + 62456007744 = 241963^2 + 249912^2 .

It is a cyclic number.

It is not a de Polignac number, because 121002101113 - 2¹ = 121002101111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121002101093 and 121002101102.

It is not an unprimeable number, because it can be changed into a prime (121002101111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3847506 + ... + 3878827.

It is an arithmetic number, because the mean of its divisors is an integer number (30252460777).

Almost surely, 2^121002101113 is an apocalyptic number.

It is an amenable number.

121002101113 is a deficient number, since it is larger than the sum of its proper divisors (7741995).

121002101113 is an equidigital number, since it uses as much as digits as its factorization.

121002101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7741994.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 121002101113 its reverse (311101200121), we get a palindrome (432103301234).

The spelling of 121002101113 in words is "one hundred twenty-one billion, two million, one hundred one thousand, one hundred thirteen".