Base | Representation |
---|---|
bin | 1011000000010101001010… |
… | …1100010001101000001011 |
3 | 1120211210000102102210122112 |
4 | 2300011102230101220023 |
5 | 3041222413403223313 |
6 | 41422450014012535 |
7 | 2356134652516343 |
oct | 260052254215013 |
9 | 46753012383575 |
10 | 12100310211083 |
11 | 39457927290a6 |
12 | 14351554a714b |
13 | 69a092563a83 |
14 | 2db92dd0dd23 |
15 | 15eb544d48a8 |
hex | b0152b11a0b |
12100310211083 has 2 divisors, whose sum is σ = 12100310211084. Its totient is φ = 12100310211082.
The previous prime is 12100310211001. The next prime is 12100310211127. The reversal of 12100310211083 is 38011201300121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12100310211083 - 218 = 12100309948939 is a prime.
It is not a weakly prime, because it can be changed into another prime (12100310231083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050155105541 + 6050155105542.
It is an arithmetic number, because the mean of its divisors is an integer number (6050155105542).
Almost surely, 212100310211083 is an apocalyptic number.
12100310211083 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100310211083 is an equidigital number, since it uses as much as digits as its factorization.
12100310211083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 23.
The spelling of 12100310211083 in words is "twelve trillion, one hundred billion, three hundred ten million, two hundred eleven thousand, eighty-three".
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