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12100401341 = 710716155409
BaseRepresentation
bin10110100010011110…
…10111100010111101
31011020022001002002122
423101033113202331
5144240200320331
65320413332325
7605600500010
oct132117274275
934208032078
1012100401341
11514a3a7696
1224184970a5
1311aabb8bc2
1482b0b5377
154ac4a417b
hex2d13d78bd

12100401341 has 8 divisors (see below), whose sum is σ = 13958274240. Its totient is φ = 10274839488.

The previous prime is 12100401311. The next prime is 12100401343. The reversal of 12100401341 is 14310400121.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12100401341 is a prime.

It is a super-2 number, since 2×121004013412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12100401343) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8076956 + ... + 8078453.

It is an arithmetic number, because the mean of its divisors is an integer number (1744784280).

Almost surely, 212100401341 is an apocalyptic number.

It is an amenable number.

12100401341 is a deficient number, since it is larger than the sum of its proper divisors (1857872899).

12100401341 is a wasteful number, since it uses less digits than its factorization.

12100401341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16155523.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12100401341 its reverse (14310400121), we get a palindrome (26410801462).

The spelling of 12100401341 in words is "twelve billion, one hundred million, four hundred one thousand, three hundred forty-one".

Divisors: 1 7 107 749 16155409 113087863 1728628763 12100401341