12101020031 has 2 divisors, whose sum is σ = 12101020032. Its totient is φ = 12101020030.

The previous prime is 12101020027. The next prime is 12101020033. The reversal of 12101020031 is 13002010121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12101020031 - 2² = 12101020027 is a prime.

It is a super-3 number, since 3×12101020031³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 12101020033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12101019994 and 12101020021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12101020033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050510015 + 6050510016.

It is an arithmetic number, because the mean of its divisors is an integer number (6050510016).

Almost surely, 2^12101020031 is an apocalyptic number.

12101020031 is a deficient number, since it is larger than the sum of its proper divisors (1).

12101020031 is an equidigital number, since it uses as much as digits as its factorization.

12101020031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 12101020031 its reverse (13002010121), we get a palindrome (25103030152).

The spelling of 12101020031 in words is "twelve billion, one hundred one million, twenty thousand, thirty-one".