Base | Representation |
---|---|
bin | 1011000000010111110100… |
… | …1011110001110000100110 |
3 | 1120211211212002212221011201 |
4 | 2300011331023301300212 |
5 | 3041230343404042410 |
6 | 41423044441553114 |
7 | 2356161430212343 |
oct | 260057513616046 |
9 | 46754762787151 |
10 | 12101023112230 |
11 | 394601908a2a8 |
12 | 14353141a579a |
13 | 69a17716c380 |
14 | 2db99a8857ca |
15 | 15eb96da483a |
hex | b017d2f1c26 |
12101023112230 has 32 divisors (see below), whose sum is σ = 23699196438624. Its totient is φ = 4422007489536.
The previous prime is 12101023112147. The next prime is 12101023112237. The reversal of 12101023112230 is 3221132010121.
It is a junction number, because it is equal to n+sod(n) for n = 12101023112198 and 12101023112207.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12101023112237) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 479805912 + ... + 479831131.
It is an arithmetic number, because the mean of its divisors is an integer number (740599888707).
Almost surely, 212101023112230 is an apocalyptic number.
12101023112230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12101023112230 is a deficient number, since it is larger than the sum of its proper divisors (11598173326394).
12101023112230 is a wasteful number, since it uses less digits than its factorization.
12101023112230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 959637160.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 12101023112230 its reverse (3221132010121), we get a palindrome (15322155122351).
The spelling of 12101023112230 in words is "twelve trillion, one hundred one billion, twenty-three million, one hundred twelve thousand, two hundred thirty".
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