121011433 has 4 divisors (see below), whose sum is σ = 122209668. Its totient is φ = 119813200.

The previous prime is 121011413. The next prime is 121011463. The reversal of 121011433 is 334110121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 99361024 + 21650409 = 9968^2 + 4653^2 .

It is a cyclic number.

It is not a de Polignac number, because 121011433 - 2⁹ = 121010921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121011413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 598966 + ... + 599167.

It is an arithmetic number, because the mean of its divisors is an integer number (30552417).

Almost surely, 2^121011433 is an apocalyptic number.

It is an amenable number.

121011433 is a deficient number, since it is larger than the sum of its proper divisors (1198235).

121011433 is a wasteful number, since it uses less digits than its factorization.

121011433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1198234.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 121011433 is about 11000.5196695429. The cubic root of 121011433 is about 494.6243219659.

Adding to 121011433 its reverse (334110121), we get a palindrome (455121554).

The spelling of 121011433 in words is "one hundred twenty-one million, eleven thousand, four hundred thirty-three".