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12102013120013 is a prime number
BaseRepresentation
bin1011000000011011100000…
…1100010110111000001101
31120211221102002202112112122
42300012320030112320031
53041234410324320023
641423331005142325
72356225111145405
oct260067014267015
946757362675478
1012102013120013
1139464869a8853
12143554b85a9a5
1369a2a42bb3ab
142dba52151805
1515ec03c602c8
hexb01b8316e0d

12102013120013 has 2 divisors, whose sum is σ = 12102013120014. Its totient is φ = 12102013120012.

The previous prime is 12102013119967. The next prime is 12102013120037. The reversal of 12102013120013 is 31002131020121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7310388435529 + 4791624684484 = 2703773^2 + 2188978^2 .

It is an emirp because it is prime and its reverse (31002131020121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12102013120013 - 26 = 12102013119949 is a prime.

It is a super-2 number, since 2×121020131200132 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12102013119973 and 12102013120000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12102013122013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051006560006 + 6051006560007.

It is an arithmetic number, because the mean of its divisors is an integer number (6051006560007).

Almost surely, 212102013120013 is an apocalyptic number.

It is an amenable number.

12102013120013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12102013120013 is an equidigital number, since it uses as much as digits as its factorization.

12102013120013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12102013120013 its reverse (31002131020121), we get a palindrome (43104144140134).

The spelling of 12102013120013 in words is "twelve trillion, one hundred two billion, thirteen million, one hundred twenty thousand, thirteen".