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12102031113120 = 2534513110365123
BaseRepresentation
bin1011000000011011100101…
…0000111111101110100000
31120211221110100121200110000
42300012321100333232200
53041234424431104440
641423332450540000
72356225420115424
oct260067120775640
946757410550400
1012102031113120
113946496078293
121435555897600
1369a2a7c4b1c0
142dba546b6b84
1515ec05616730
hexb01b943fba0

12102031113120 has 480 divisors, whose sum is σ = 46037883209472. Its totient is φ = 2976215021568.

The previous prime is 12102031113119. The next prime is 12102031113173. The reversal of 12102031113120 is 2131113020121.

12102031113120 is a `hidden beast` number, since 1 + 21 + 0 + 20 + 311 + 1 + 312 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (480).

It is a super-2 number, since 2×121020311131202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 12102031113093 and 12102031113102.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 185800879 + ... + 185866001.

Almost surely, 212102031113120 is an apocalyptic number.

12102031113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12102031113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23018941604736).

12102031113120 is an abundant number, since it is smaller than the sum of its proper divisors (33935852096352).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12102031113120 is a wasteful number, since it uses less digits than its factorization.

12102031113120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66266 (or 66249 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 12102031113120 its reverse (2131113020121), we get a palindrome (14233144133241).

The spelling of 12102031113120 in words is "twelve trillion, one hundred two billion, thirty-one million, one hundred thirteen thousand, one hundred twenty".