Base | Representation |
---|---|
bin | 10001100111000110010… |
… | …000110100111010111011 |
3 | 11021200202202121001100011 |
4 | 101213012100310322323 |
5 | 124312003300010021 |
6 | 2323544101322351 |
7 | 153302120130352 |
oct | 21470620647273 |
9 | 4250682531304 |
10 | 1210212110011 |
11 | 427280205533 |
12 | 1766697063b7 |
13 | 8a17920c558 |
14 | 42808902999 |
15 | 217314e5de1 |
hex | 119c6434ebb |
1210212110011 has 2 divisors, whose sum is σ = 1210212110012. Its totient is φ = 1210212110010.
The previous prime is 1210212109979. The next prime is 1210212110071. The reversal of 1210212110011 is 1100112120121.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1210212110011 - 25 = 1210212109979 is a prime.
It is a super-2 number, since 2×12102121100112 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1210212109973 and 1210212110000.
It is not a weakly prime, because it can be changed into another prime (1210212110071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605106055005 + 605106055006.
It is an arithmetic number, because the mean of its divisors is an integer number (605106055006).
Almost surely, 21210212110011 is an apocalyptic number.
1210212110011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210212110011 is an equidigital number, since it uses as much as digits as its factorization.
1210212110011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 1210212110011 its reverse (1100112120121), we get a palindrome (2310324230132).
The spelling of 1210212110011 in words is "one trillion, two hundred ten billion, two hundred twelve million, one hundred ten thousand, eleven".
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