Base | Representation |
---|---|
bin | 111000010110101101… |
… | …1010100010100010000 |
3 | 102120101011202222010120 |
4 | 1300231123110110100 |
5 | 3440322413020422 |
6 | 131332452430240 |
7 | 11513006253342 |
oct | 1605533242420 |
9 | 376334688116 |
10 | 121021220112 |
11 | 47363361991 |
12 | 1b555918380 |
13 | b548944120 |
14 | 5c00c19292 |
15 | 323497945c |
hex | 1c2d6d4510 |
121021220112 has 40 divisors (see below), whose sum is σ = 336687242304. Its totient is φ = 37237298304.
The previous prime is 121021220101. The next prime is 121021220113. The reversal of 121021220112 is 211022120121.
121021220112 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1210212201123 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 121021220091 and 121021220100.
It is not an unprimeable number, because it can be changed into a prime (121021220113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 96971508 + ... + 96972755.
Almost surely, 2121021220112 is an apocalyptic number.
121021220112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
121021220112 is an abundant number, since it is smaller than the sum of its proper divisors (215666022192).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121021220112 is a wasteful number, since it uses less digits than its factorization.
121021220112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 193944287 (or 193944281 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 121021220112 its reverse (211022120121), we get a palindrome (332043340233).
Subtracting 121021220112 from its reverse (211022120121), we obtain a palindrome (90000900009).
The spelling of 121021220112 in words is "one hundred twenty-one billion, twenty-one million, two hundred twenty thousand, one hundred twelve".
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