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12102332101200 = 24325211305614447
BaseRepresentation
bin1011000000011100101100…
…1101001011001001010000
31120211222020022222110110200
42300013023031023021100
53041241034004214300
641423422402055200
72356236033351615
oct260071315131120
946758208873420
1012102332101200
11394662aa67070
12143561a64a500
1369a325403963
142dba8266650c
1515ec21c6d200
hexb01cb34b250

12102332101200 has 180 divisors, whose sum is σ = 45816495586368. Its totient is φ = 2933898681600.

The previous prime is 12102332101187. The next prime is 12102332101201. The reversal of 12102332101200 is 210123320121.

12102332101200 is a `hidden beast` number, since 1 + 21 + 0 + 233 + 210 + 1 + 200 = 666.

It is a tau number, because it is divible by the number of its divisors (180).

It is a super-4 number, since 4×121023321012004 (a number of 53 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12102332101201) by changing a digit.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 152767624 + ... + 152846823.

Almost surely, 212102332101200 is an apocalyptic number.

12102332101200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12102332101200 is an abundant number, since it is smaller than the sum of its proper divisors (33714163485168).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12102332101200 is a wasteful number, since it uses less digits than its factorization.

12102332101200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 305614482 (or 305614468 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 12102332101200 its reverse (210123320121), we get a palindrome (12312455421321).

It can be divided in two parts, 121023 and 32101200, that added together give a palindrome (32222223).

The spelling of 12102332101200 in words is "twelve trillion, one hundred two billion, three hundred thirty-two million, one hundred one thousand, two hundred".