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12105131 is a prime number
BaseRepresentation
bin101110001011…
…010110101011
3211210000010012
4232023112223
511044331011
61111242135
7204614633
oct56132653
924700105
1012105131
116918845
12407934b
13267aacc
1418716c3
1510e1a8b
hexb8b5ab

12105131 has 2 divisors, whose sum is σ = 12105132. Its totient is φ = 12105130.

The previous prime is 12105113. The next prime is 12105133. The reversal of 12105131 is 13150121.

Together with previous prime (12105113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12105131 is a prime.

It is a super-2 number, since 2×121051312 = 293068393054322, which contains 22 as substring.

Together with 12105133, it forms a pair of twin primes.

It is a Chen prime.

It is a plaindrome in base 13.

It is not a weakly prime, because it can be changed into another prime (12105133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052565 + 6052566.

It is an arithmetic number, because the mean of its divisors is an integer number (6052566).

Almost surely, 212105131 is an apocalyptic number.

12105131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12105131 is an equidigital number, since it uses as much as digits as its factorization.

12105131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 14.

The square root of 12105131 is about 3479.2428774088. The cubic root of 12105131 is about 229.6094885641.

Adding to 12105131 its reverse (13150121), we get a palindrome (25255252).

The spelling of 12105131 in words is "twelve million, one hundred five thousand, one hundred thirty-one".