12110005111 has 2 divisors, whose sum is σ = 12110005112. Its totient is φ = 12110005110.

The previous prime is 12110005109. The next prime is 12110005133. The reversal of 12110005111 is 11150001121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12110005111 - 2¹ = 12110005109 is a prime.

It is a super-2 number, since 2×12110005111² (a number of 21 digits) contains 22 as substring.

Together with 12110005109, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12110005091 and 12110005100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12110005151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055002555 + 6055002556.

It is an arithmetic number, because the mean of its divisors is an integer number (6055002556).

Almost surely, 2^12110005111 is an apocalyptic number.

12110005111 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110005111 is an equidigital number, since it uses as much as digits as its factorization.

12110005111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10, while the sum is 13.

Adding to 12110005111 its reverse (11150001121), we get a palindrome (23260006232).

The spelling of 12110005111 in words is "twelve billion, one hundred ten million, five thousand, one hundred eleven".