Base | Representation |
---|---|
bin | 10001100111110101010… |
… | …010001101010011111011 |
3 | 11021202210202000212121202 |
4 | 101213311102031103323 |
5 | 124320112224014321 |
6 | 2324154242124415 |
7 | 153330506445611 |
oct | 21476522152373 |
9 | 4252722025552 |
10 | 1211001001211 |
11 | 427645549131 |
12 | 17684995070b |
13 | 8a2737a2c91 |
14 | 428815b96b1 |
15 | 2177a8c670b |
hex | 119f548d4fb |
1211001001211 has 2 divisors, whose sum is σ = 1211001001212. Its totient is φ = 1211001001210.
The previous prime is 1211001001207. The next prime is 1211001001229. The reversal of 1211001001211 is 1121001001121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1211001001211 - 22 = 1211001001207 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1211001001192 and 1211001001201.
It is not a weakly prime, because it can be changed into another prime (1211001001201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605500500605 + 605500500606.
It is an arithmetic number, because the mean of its divisors is an integer number (605500500606).
Almost surely, 21211001001211 is an apocalyptic number.
1211001001211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211001001211 is an equidigital number, since it uses as much as digits as its factorization.
1211001001211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 1211001001211 its reverse (1121001001121), we get a palindrome (2332002002332).
The spelling of 1211001001211 in words is "one trillion, two hundred eleven billion, one million, one thousand, two hundred eleven".
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