121100113111 has 2 divisors, whose sum is σ = 121100113112. Its totient is φ = 121100113110.

The previous prime is 121100113109. The next prime is 121100113117. The reversal of 121100113111 is 111311001121.

It is a weak prime.

It is an emirp because it is prime and its reverse (111311001121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121100113111 - 2¹ = 121100113109 is a prime.

Together with 121100113109, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 121100113091 and 121100113100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121100113117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60550056555 + 60550056556.

It is an arithmetic number, because the mean of its divisors is an integer number (60550056556).

Almost surely, 2^121100113111 is an apocalyptic number.

121100113111 is a deficient number, since it is larger than the sum of its proper divisors (1).

121100113111 is an equidigital number, since it uses as much as digits as its factorization.

121100113111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 121100113111 its reverse (111311001121), we get a palindrome (232411114232).

The spelling of 121100113111 in words is "one hundred twenty-one billion, one hundred million, one hundred thirteen thousand, one hundred eleven".