Base | Representation |
---|---|
bin | 11011100010001111010110… |
… | …011110000000011110011100 |
3 | 120212210001210020020210200020 |
4 | 123202033112132000132130 |
5 | 111333101202440214322 |
6 | 1105320355300432140 |
7 | 34336125606223464 |
oct | 3342172636003634 |
9 | 525701706223606 |
10 | 121100201101212 |
11 | 3564a34149a553 |
12 | 116ba0443a8650 |
13 | 5275913a86538 |
14 | 21c93d1124ba4 |
15 | e00162acc05c |
hex | 6e23d678079c |
121100201101212 has 12 divisors (see below), whose sum is σ = 282567135902856. Its totient is φ = 40366733700400.
The previous prime is 121100201101207. The next prime is 121100201101223. The reversal of 121100201101212 is 212101102001121.
It is a happy number.
121100201101212 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 121100201101191 and 121100201101200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5045841712539 + ... + 5045841712562.
It is an arithmetic number, because the mean of its divisors is an integer number (23547261325238).
Almost surely, 2121100201101212 is an apocalyptic number.
121100201101212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
121100201101212 is an abundant number, since it is smaller than the sum of its proper divisors (161466934801644).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121100201101212 is a wasteful number, since it uses less digits than its factorization.
121100201101212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10091683425108 (or 10091683425106 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 15.
Adding to 121100201101212 its reverse (212101102001121), we get a palindrome (333201303102333).
The spelling of 121100201101212 in words is "one hundred twenty-one trillion, one hundred billion, two hundred one million, one hundred one thousand, two hundred twelve".
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