1211002100111 has 4 divisors (see below), whose sum is σ = 1217087538000. Its totient is φ = 1204916662224.

The previous prime is 1211002100029. The next prime is 1211002100117. The reversal of 1211002100111 is 1110012001121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1211002100111 - 2¹⁴ = 1211002083727 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1211002100092 and 1211002100101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211002100117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3042718646 + ... + 3042719043.

It is an arithmetic number, because the mean of its divisors is an integer number (304271884500).

Almost surely, 2^{1211002100111} is an apocalyptic number.

1211002100111 is a deficient number, since it is larger than the sum of its proper divisors (6085437889).

1211002100111 is an equidigital number, since it uses as much as digits as its factorization.

1211002100111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6085437888.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 1211002100111 its reverse (1110012001121), we get a palindrome (2321014101232).

The spelling of 1211002100111 in words is "one trillion, two hundred eleven billion, two million, one hundred thousand, one hundred eleven".