Base | Representation |
---|---|
bin | 111000011001000110… |
… | …0001001110101101000 |
3 | 102120120202010212102020 |
4 | 1300302030021311220 |
5 | 3441003342143422 |
6 | 131344425304440 |
7 | 11514666426123 |
oct | 1606214116550 |
9 | 376522125366 |
10 | 121101131112 |
11 | 473a4482235 |
12 | 1b578635120 |
13 | b55c372b40 |
14 | 5c0b69b3ba |
15 | 323b9b195c |
hex | 1c32309d68 |
121101131112 has 32 divisors (see below), whose sum is σ = 326041507680. Its totient is φ = 37261886400.
The previous prime is 121101130981. The next prime is 121101131113. The reversal of 121101131112 is 211131101121.
It is a junction number, because it is equal to n+sod(n) for n = 121101131091 and 121101131100.
It is not an unprimeable number, because it can be changed into a prime (121101131113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 194072014 + ... + 194072637.
It is an arithmetic number, because the mean of its divisors is an integer number (10188797115).
Almost surely, 2121101131112 is an apocalyptic number.
121101131112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
121101131112 is an abundant number, since it is smaller than the sum of its proper divisors (204940376568).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121101131112 is a wasteful number, since it uses less digits than its factorization.
121101131112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 388144673 (or 388144669 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 15.
Adding to 121101131112 its reverse (211131101121), we get a palindrome (332232232233).
The spelling of 121101131112 in words is "one hundred twenty-one billion, one hundred one million, one hundred thirty-one thousand, one hundred twelve".
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