Base | Representation |
---|---|
bin | 10001100111110110011… |
… | …111010011100111000111 |
3 | 11021202212011001200202022 |
4 | 101213312133103213013 |
5 | 124320132412241403 |
6 | 2324200243233355 |
7 | 153331143313523 |
oct | 21476637234707 |
9 | 4252764050668 |
10 | 1211021212103 |
11 | 4276559a294a |
12 | 17685467885b |
13 | 8a277a2b3a1 |
14 | 4288415ad83 |
15 | 2177c569d38 |
hex | 119f67d39c7 |
1211021212103 has 2 divisors, whose sum is σ = 1211021212104. Its totient is φ = 1211021212102.
The previous prime is 1211021212091. The next prime is 1211021212123. The reversal of 1211021212103 is 3012121201121.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (3012121201121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1211021212103 - 24 = 1211021212087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211021212123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605510606051 + 605510606052.
It is an arithmetic number, because the mean of its divisors is an integer number (605510606052).
Almost surely, 21211021212103 is an apocalyptic number.
1211021212103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211021212103 is an equidigital number, since it uses as much as digits as its factorization.
1211021212103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1211021212103 its reverse (3012121201121), we get a palindrome (4223142413224).
The spelling of 1211021212103 in words is "one trillion, two hundred eleven billion, twenty-one million, two hundred twelve thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •