Base | Representation |
---|---|
bin | 1011000000111100111111… |
… | …1010011110011100110011 |
3 | 1120212210121111002011202011 |
4 | 2300033033322132130303 |
5 | 3041411312230121321 |
6 | 41431414515103351 |
7 | 2356663616063152 |
oct | 260171772363463 |
9 | 46783544064664 |
10 | 12111001020211 |
11 | 394a279385245 |
12 | 14372398a1b57 |
13 | 69b0a73c3132 |
14 | 2dc265ad7599 |
15 | 16007cd4bae1 |
hex | b03cfe9e733 |
12111001020211 has 2 divisors, whose sum is σ = 12111001020212. Its totient is φ = 12111001020210.
The previous prime is 12111001020193. The next prime is 12111001020221. The reversal of 12111001020211 is 11202010011121.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12111001020211 - 217 = 12111000889139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12111001020191 and 12111001020200.
It is not a weakly prime, because it can be changed into another prime (12111001020221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055500510105 + 6055500510106.
It is an arithmetic number, because the mean of its divisors is an integer number (6055500510106).
Almost surely, 212111001020211 is an apocalyptic number.
12111001020211 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111001020211 is an equidigital number, since it uses as much as digits as its factorization.
12111001020211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 12111001020211 its reverse (11202010011121), we get a palindrome (23313011031332).
The spelling of 12111001020211 in words is "twelve trillion, one hundred eleven billion, one million, twenty thousand, two hundred eleven".
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