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121111102099999 = 1111010100190909
BaseRepresentation
bin11011100010011001100000…
…001110000001001000011111
3120212211002220221101220210001
4123202121200032001020133
5111333241014114144444
61105325401110555131
734336663004204164
oct3342314016011037
9525732827356701
10121111102099999
1135653a25859260
1211700187068aa7
135276960329b8b
1421c9b46bc406b
15e0059eb128d4
hex6e266038121f

121111102099999 has 4 divisors (see below), whose sum is σ = 132121202290920. Its totient is φ = 110101001909080.

The previous prime is 121111102099993. The next prime is 121111102100017. The reversal of 121111102099999 is 999990201111121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121111102099999 - 29 = 121111102099487 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121111102099993) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5505050095444 + ... + 5505050095465.

It is an arithmetic number, because the mean of its divisors is an integer number (33030300572730).

Almost surely, 2121111102099999 is an apocalyptic number.

121111102099999 is a deficient number, since it is larger than the sum of its proper divisors (11010100190921).

121111102099999 is a wasteful number, since it uses less digits than its factorization.

121111102099999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11010100190920.

The product of its (nonzero) digits is 236196, while the sum is 55.

The spelling of 121111102099999 in words is "one hundred twenty-one trillion, one hundred eleven billion, one hundred two million, ninety-nine thousand, nine hundred ninety-nine".

Divisors: 1 11 11010100190909 121111102099999