Base | Representation |
---|---|
bin | 10110100011110001… |
… | …00110111010101111 |
3 | 1011021001101022211002 |
4 | 23101320212322233 |
5 | 144300432242312 |
6 | 5321441150515 |
7 | 606061414403 |
oct | 132170467257 |
9 | 34231338732 |
10 | 12111212207 |
11 | 5155510a96 |
12 | 242002b43b |
13 | 11b0202873 |
14 | 82c6cb103 |
15 | 4ad3dc4c2 |
hex | 2d1e26eaf |
12111212207 has 2 divisors, whose sum is σ = 12111212208. Its totient is φ = 12111212206.
The previous prime is 12111212167. The next prime is 12111212209. The reversal of 12111212207 is 70221211121.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12111212207 - 28 = 12111211951 is a prime.
It is a super-2 number, since 2×121112122072 (a number of 21 digits) contains 22 as substring.
Together with 12111212209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12111212209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055606103 + 6055606104.
It is an arithmetic number, because the mean of its divisors is an integer number (6055606104).
Almost surely, 212111212207 is an apocalyptic number.
12111212207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111212207 is an equidigital number, since it uses as much as digits as its factorization.
12111212207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 12111212207 its reverse (70221211121), we get a palindrome (82332423328).
The spelling of 12111212207 in words is "twelve billion, one hundred eleven million, two hundred twelve thousand, two hundred seven".
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