12111213319 has 2 divisors, whose sum is σ = 12111213320. Its totient is φ = 12111213318.

The previous prime is 12111213281. The next prime is 12111213343. The reversal of 12111213319 is 91331211121.

12111213319 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12111213319 - 2¹⁵ = 12111180551 is a prime.

It is a super-2 number, since 2×12111213319² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12111213293 and 12111213302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12111213349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055606659 + 6055606660.

It is an arithmetic number, because the mean of its divisors is an integer number (6055606660).

Almost surely, 2^12111213319 is an apocalyptic number.

12111213319 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111213319 is an equidigital number, since it uses as much as digits as its factorization.

12111213319 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 324, while the sum is 25.

It can be divided in two parts, 121112 and 13319, that added together give a palindrome (134431).

The spelling of 12111213319 in words is "twelve billion, one hundred eleven million, two hundred thirteen thousand, three hundred nineteen".