121113301135230 has 48 divisors (see below), whose sum is σ = 315920298277584. Its totient is φ = 32191678730880.

The previous prime is 121113301135219. The next prime is 121113301135289. The reversal of 121113301135230 is 32531103311121.

121113301135230 is a `hidden beast` number, since 1 + 2 + 1 + 1 + 1 + 3 + 301 + 1 + 352 + 3 + 0 = 666.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 121113301135194 and 121113301135203.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2191671631 + ... + 2191726890.

It is an arithmetic number, because the mean of its divisors is an integer number (6581672880783).

Almost surely, 2^{121113301135230} is an apocalyptic number.

121113301135230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

121113301135230 is an abundant number, since it is smaller than the sum of its proper divisors (194806997142354).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121113301135230 is a wasteful number, since it uses less digits than its factorization.

121113301135230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4383398841 (or 4383398838 counting only the distinct ones).

The product of its (nonzero) digits is 1620, while the sum is 27.

Adding to 121113301135230 its reverse (32531103311121), we get a palindrome (153644404446351).

The spelling of 121113301135230 in words is "one hundred twenty-one trillion, one hundred thirteen billion, three hundred one million, one hundred thirty-five thousand, two hundred thirty".