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12112120133 = 19637480007
BaseRepresentation
bin10110100011111000…
…00100100101000101
31011021010002110020222
423101330010211011
5144301200321013
65321512434125
7606102215411
oct132174044505
934233073228
1012112120133
115155a81143
1224203a8945
1311b045cbb9
1482c885d41
154ad51b508
hex2d1f04945

12112120133 has 4 divisors (see below), whose sum is σ = 12749600160. Its totient is φ = 11474640108.

The previous prime is 12112120127. The next prime is 12112120187. The reversal of 12112120133 is 33102121121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12112120133 - 210 = 12112119109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12112120333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318739985 + ... + 318740022.

It is an arithmetic number, because the mean of its divisors is an integer number (3187400040).

Almost surely, 212112120133 is an apocalyptic number.

It is an amenable number.

12112120133 is a deficient number, since it is larger than the sum of its proper divisors (637480027).

12112120133 is an equidigital number, since it uses as much as digits as its factorization.

12112120133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 637480026.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12112120133 its reverse (33102121121), we get a palindrome (45214241254).

The spelling of 12112120133 in words is "twelve billion, one hundred twelve million, one hundred twenty thousand, one hundred thirty-three".

Divisors: 1 19 637480007 12112120133