1211241144431 has 2 divisors, whose sum is σ = 1211241144432. Its totient is φ = 1211241144430.

The previous prime is 1211241144427. The next prime is 1211241144433. The reversal of 1211241144431 is 1344411421121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1211241144431 - 2² = 1211241144427 is a prime.

It is a super-2 number, since 2×1211241144431² (a number of 25 digits) contains 22 as substring.

Together with 1211241144433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1211241144394 and 1211241144403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211241144433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605620572215 + 605620572216.

It is an arithmetic number, because the mean of its divisors is an integer number (605620572216).

Almost surely, 2^{1211241144431} is an apocalyptic number.

1211241144431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211241144431 is an equidigital number, since it uses as much as digits as its factorization.

1211241144431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3072, while the sum is 29.

Adding to 1211241144431 its reverse (1344411421121), we get a palindrome (2555652565552).

The spelling of 1211241144431 in words is "one trillion, two hundred eleven billion, two hundred forty-one million, one hundred forty-four thousand, four hundred thirty-one".