121131040453 has 2 divisors, whose sum is σ = 121131040454. Its totient is φ = 121131040452.

The previous prime is 121131040451. The next prime is 121131040483. The reversal of 121131040453 is 354040131121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113412012289 + 7719028164 = 336767^2 + 87858^2 .

It is a cyclic number.

It is not a de Polignac number, because 121131040453 - 2¹ = 121131040451 is a prime.

It is a super-2 number, since 2×121131040453² (a number of 23 digits) contains 22 as substring.

Together with 121131040451, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121131040451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565520226 + 60565520227.

It is an arithmetic number, because the mean of its divisors is an integer number (60565520227).

Almost surely, 2^121131040453 is an apocalyptic number.

It is an amenable number.

121131040453 is a deficient number, since it is larger than the sum of its proper divisors (1).

121131040453 is an equidigital number, since it uses as much as digits as its factorization.

121131040453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 121131040453 its reverse (354040131121), we get a palindrome (475171171574).

The spelling of 121131040453 in words is "one hundred twenty-one billion, one hundred thirty-one million, forty thousand, four hundred fifty-three".