Base | Representation |
---|---|
bin | 10110100011111111… |
… | …10110100011111101 |
3 | 1011021011221210212121 |
4 | 23101333312203331 |
5 | 144301424030133 |
6 | 5321550002541 |
7 | 606113514163 |
oct | 132177664375 |
9 | 34234853777 |
10 | 12113111293 |
11 | 5156598888 |
12 | 24207a6451 |
13 | 11b071909a |
14 | 82ca63233 |
15 | 4ad66502d |
hex | 2d1ff68fd |
12113111293 has 2 divisors, whose sum is σ = 12113111294. Its totient is φ = 12113111292.
The previous prime is 12113111279. The next prime is 12113111333. The reversal of 12113111293 is 39211131121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8071584964 + 4041526329 = 89842^2 + 63573^2 .
It is a cyclic number.
It is not a de Polignac number, because 12113111293 - 25 = 12113111261 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12113111693) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056555646 + 6056555647.
It is an arithmetic number, because the mean of its divisors is an integer number (6056555647).
Almost surely, 212113111293 is an apocalyptic number.
It is an amenable number.
12113111293 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113111293 is an equidigital number, since it uses as much as digits as its factorization.
12113111293 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 324, while the sum is 25.
The spelling of 12113111293 in words is "twelve billion, one hundred thirteen million, one hundred eleven thousand, two hundred ninety-three".
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