Base | Representation |
---|---|
bin | 10110100011111111… |
… | …10110100100000111 |
3 | 1011021011221210212222 |
4 | 23101333312210013 |
5 | 144301424030203 |
6 | 5321550002555 |
7 | 606113514206 |
oct | 132177664407 |
9 | 34234853788 |
10 | 12113111303 |
11 | 5156598897 |
12 | 24207a645b |
13 | 11b07190a7 |
14 | 82ca6323d |
15 | 4ad665038 |
hex | 2d1ff6907 |
12113111303 has 8 divisors (see below), whose sum is σ = 12827333088. Its totient is φ = 11399076864.
The previous prime is 12113111293. The next prime is 12113111333. The reversal of 12113111303 is 30311131121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12113111303 - 210 = 12113110279 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12113111333) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 99350 + ... + 184652.
It is an arithmetic number, because the mean of its divisors is an integer number (1603416636).
Almost surely, 212113111303 is an apocalyptic number.
12113111303 is a deficient number, since it is larger than the sum of its proper divisors (714221785).
12113111303 is an equidigital number, since it uses as much as digits as its factorization.
12113111303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93673.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 12113111303 its reverse (30311131121), we get a palindrome (42424242424).
The spelling of 12113111303 in words is "twelve billion, one hundred thirteen million, one hundred eleven thousand, three hundred three".
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