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12113111312303 = 37327381386819
BaseRepresentation
bin1011000001000100110110…
…1100100110011110101111
31120220000001112222010021112
42300101031230212132233
53041430122443443203
641432404142022235
72360100122214221
oct260211554463657
946800045863245
1012113111312303
1139501616029a1
12143772857797b
1369b352675791
142dc3c60a2411
151601532486d8
hexb044db267af

12113111312303 has 4 divisors (see below), whose sum is σ = 12440492699160. Its totient is φ = 11785729925448.

The previous prime is 12113111312221. The next prime is 12113111312359. The reversal of 12113111312303 is 30321311131121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12113111312303 - 228 = 12112842876847 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12113111312383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163690693373 + ... + 163690693446.

It is an arithmetic number, because the mean of its divisors is an integer number (3110123174790).

Almost surely, 212113111312303 is an apocalyptic number.

12113111312303 is a deficient number, since it is larger than the sum of its proper divisors (327381386857).

12113111312303 is an equidigital number, since it uses as much as digits as its factorization.

12113111312303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 327381386856.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 12113111312303 its reverse (30321311131121), we get a palindrome (42434422443424).

The spelling of 12113111312303 in words is "twelve trillion, one hundred thirteen billion, one hundred eleven million, three hundred twelve thousand, three hundred three".

Divisors: 1 37 327381386819 12113111312303