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121131201203 = 124996982547
BaseRepresentation
bin111000011001111111…
…0110111001010110011
3102120122211201120211022
41300303332313022303
53441034041414303
6131351422010055
711515513136045
oct1606376671263
9376584646738
10121131201203
114740a450351
121b58671692b
13b5656709ac
145c11687a95
15323e451438
hex1c33fb72b3

121131201203 has 4 divisors (see below), whose sum is σ = 121228185000. Its totient is φ = 121034217408.

The previous prime is 121131201187. The next prime is 121131201253. The reversal of 121131201203 is 302102131121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121131201203 - 24 = 121131201187 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121131201253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48490025 + ... + 48492522.

It is an arithmetic number, because the mean of its divisors is an integer number (30307046250).

Almost surely, 2121131201203 is an apocalyptic number.

121131201203 is a deficient number, since it is larger than the sum of its proper divisors (96983797).

121131201203 is an equidigital number, since it uses as much as digits as its factorization.

121131201203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96983796.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 121131201203 its reverse (302102131121), we get a palindrome (423233332324).

The spelling of 121131201203 in words is "one hundred twenty-one billion, one hundred thirty-one million, two hundred one thousand, two hundred three".

Divisors: 1 1249 96982547 121131201203