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1211321000023 is a prime number
BaseRepresentation
bin10001101000001000010…
…110111010000001010111
311021210122001011111110121
4101220020112322001113
5124321241134000043
62324250112532411
7153341443421011
oct21501026720127
94253561144417
101211321000023
1142779a141a62
12176918b51107
138a2c4b837a4
14428b1cb71b1
1521798a35ded
hex11a085ba057

1211321000023 has 2 divisors, whose sum is σ = 1211321000024. Its totient is φ = 1211321000022.

The previous prime is 1211320999991. The next prime is 1211321000027. The reversal of 1211321000023 is 3200001231121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1211321000023 - 25 = 1211320999991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1211320999970 and 1211321000006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211321000027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605660500011 + 605660500012.

It is an arithmetic number, because the mean of its divisors is an integer number (605660500012).

Almost surely, 21211321000023 is an apocalyptic number.

1211321000023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211321000023 is an equidigital number, since it uses as much as digits as its factorization.

1211321000023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1211321000023 its reverse (3200001231121), we get a palindrome (4411322231144).

The spelling of 1211321000023 in words is "one trillion, two hundred eleven billion, three hundred twenty-one million, twenty-three", and thus it is an aban number.