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12113300030100 = 22352233753518867
BaseRepresentation
bin1011000001000101100011…
…1100100000001010010100
31120220000112201001222102120
42300101120330200022110
53041431014301430400
641432435002535540
72360104603251663
oct260213074401224
946800481058376
1012113300030100
11395024908a415
12143777b8075b0
1369b3827ac709
142dc403188dda
15160164ac4ca0
hexb0458f20294

12113300030100 has 288 divisors, whose sum is σ = 37571311282176. Its totient is φ = 3005361216000.

The previous prime is 12113300030089. The next prime is 12113300030107. The reversal of 12113300030100 is 103000331121.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 12113300030100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12113300030107) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1366105867 + ... + 1366114733.

It is an arithmetic number, because the mean of its divisors is an integer number (130455941952).

Almost surely, 212113300030100 is an apocalyptic number.

12113300030100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12113300030100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18785655641088).

12113300030100 is an abundant number, since it is smaller than the sum of its proper divisors (25458011252076).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12113300030100 is a wasteful number, since it uses less digits than its factorization.

12113300030100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14295 (or 14288 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 12113300030100 its reverse (103000331121), we get a palindrome (12216300361221).

The spelling of 12113300030100 in words is "twelve trillion, one hundred thirteen billion, three hundred million, thirty thousand, one hundred".