12113414303 has 4 divisors (see below), whose sum is σ = 12113652000. Its totient is φ = 12113176608.

The previous prime is 12113414281. The next prime is 12113414317. The reversal of 12113414303 is 30341431121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30341431121 = 5501 ⋅5515621.

It is a cyclic number.

It is not a de Polignac number, because 12113414303 - 2⁶ = 12113414239 is a prime.

It is a super-2 number, since 2×12113414303² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12113410303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7850 + ... + 155847.

It is an arithmetic number, because the mean of its divisors is an integer number (3028413000).

Almost surely, 2^12113414303 is an apocalyptic number.

12113414303 is a deficient number, since it is larger than the sum of its proper divisors (237697).

12113414303 is an equidigital number, since it uses as much as digits as its factorization.

12113414303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 237696.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 12113414303 its reverse (30341431121), we get a palindrome (42454845424).

The spelling of 12113414303 in words is "twelve billion, one hundred thirteen million, four hundred fourteen thousand, three hundred three".