Base | Representation |
---|---|
bin | 1110011100001… |
… | …11000100010101 |
3 | 22102221112010022 |
4 | 13032013010111 |
5 | 222002430402 |
6 | 20004234525 |
7 | 3000445214 |
oct | 716070425 |
9 | 272845108 |
10 | 121139477 |
11 | 6241a978 |
12 | 3469ba45 |
13 | 1c135784 |
14 | 1213507b |
15 | a97d2a2 |
hex | 7387115 |
121139477 has 2 divisors, whose sum is σ = 121139478. Its totient is φ = 121139476.
The previous prime is 121139441. The next prime is 121139479. The reversal of 121139477 is 774931121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 120868036 + 271441 = 10994^2 + 521^2 .
It is a cyclic number.
It is not a de Polignac number, because 121139477 - 212 = 121135381 is a prime.
It is a super-3 number, since 3×1211394773 (a number of 25 digits) contains 333 as substring.
Together with 121139479, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121139479) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60569738 + 60569739.
It is an arithmetic number, because the mean of its divisors is an integer number (60569739).
Almost surely, 2121139477 is an apocalyptic number.
It is an amenable number.
121139477 is a deficient number, since it is larger than the sum of its proper divisors (1).
121139477 is an equidigital number, since it uses as much as digits as its factorization.
121139477 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10584, while the sum is 35.
The square root of 121139477 is about 11006.3380376945. The cubic root of 121139477 is about 494.7987169249.
The spelling of 121139477 in words is "one hundred twenty-one million, one hundred thirty-nine thousand, four hundred seventy-seven".
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