Base | Representation |
---|---|
bin | 11011100010110100101001… |
… | …000010100011101101111010 |
3 | 120212220220010200121111210120 |
4 | 123202310221002203231322 |
5 | 111334230203211320442 |
6 | 1105351020345154110 |
7 | 34342044050611500 |
oct | 3342645102435572 |
9 | 525826120544716 |
10 | 121140241120122 |
11 | 35665318aa1374 |
12 | 1170595978b936 |
13 | 527962520b113 |
14 | 21cb30cb4c670 |
15 | e01207d6b4ec |
hex | 6e2d290a3b7a |
121140241120122 has 96 divisors (see below), whose sum is σ = 290682835211520. Its totient is φ = 33539685379200.
The previous prime is 121140241120097. The next prime is 121140241120159. The reversal of 121140241120122 is 221021142041121.
It is a super-3 number, since 3×1211402411201223 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121140241120092 and 121140241120101.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 42004597 + ... + 44795832.
It is an arithmetic number, because the mean of its divisors is an integer number (3027946200120).
Almost surely, 2121140241120122 is an apocalyptic number.
121140241120122 is an abundant number, since it is smaller than the sum of its proper divisors (169542594091398).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121140241120122 is a wasteful number, since it uses less digits than its factorization.
121140241120122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86800596 (or 86800589 counting only the distinct ones).
The product of its (nonzero) digits is 512, while the sum is 24.
Adding to 121140241120122 its reverse (221021142041121), we get a palindrome (342161383161243).
The spelling of 121140241120122 in words is "one hundred twenty-one trillion, one hundred forty billion, two hundred forty-one million, one hundred twenty thousand, one hundred twenty-two".
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