Base | Representation |
---|---|
bin | 1011000001001000010101… |
… | …0100001000010100011000 |
3 | 1120220002110120202222022201 |
4 | 2300102011110020110120 |
5 | 3041434030332441100 |
6 | 41433040513455544 |
7 | 2360132212421005 |
oct | 260220524102430 |
9 | 46802416688281 |
10 | 12114044421400 |
11 | 39505a0299639 |
12 | 1437948b715b4 |
13 | 69b470a9233c |
14 | 2dc473d9a8ac |
15 | 1601aa11536a |
hex | b0485508518 |
12114044421400 has 24 divisors (see below), whose sum is σ = 28165153280220. Its totient is φ = 4845617768480.
The previous prime is 12114044421379. The next prime is 12114044421461. The reversal of 12114044421400 is 412444041121.
It is a super-3 number, since 3×121140444214003 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 30285110854 + ... + 30285111253.
Almost surely, 212114044421400 is an apocalyptic number.
12114044421400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12114044421400 is an abundant number, since it is smaller than the sum of its proper divisors (16051108858820).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12114044421400 is a wasteful number, since it uses less digits than its factorization.
12114044421400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60570222123 (or 60570222114 counting only the distinct ones).
The product of its (nonzero) digits is 4096, while the sum is 28.
Adding to 12114044421400 its reverse (412444041121), we get a palindrome (12526488462521).
The spelling of 12114044421400 in words is "twelve trillion, one hundred fourteen billion, forty-four million, four hundred twenty-one thousand, four hundred".
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