12114300040 has 32 divisors (see below), whose sum is σ = 27299623680. Its totient is φ = 4838173632.

The previous prime is 12114300019. The next prime is 12114300049. The reversal of 12114300040 is 4000341121.

It is a super-3 number, since 3×12114300040³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12114299987 and 12114300023.

It is not an unprimeable number, because it can be changed into a prime (12114300049) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 209784 + ... + 261223.

It is an arithmetic number, because the mean of its divisors is an integer number (853113240).

Almost surely, 2^12114300040 is an apocalyptic number.

12114300040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12114300040 is an abundant number, since it is smaller than the sum of its proper divisors (15185323640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12114300040 is a wasteful number, since it uses less digits than its factorization.

12114300040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 471661 (or 471657 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 12114300040 its reverse (4000341121), we get a palindrome (16114641161).

The spelling of 12114300040 in words is "twelve billion, one hundred fourteen million, three hundred thousand, forty".